در این نوشته کد ها و نمونه مثال هایی برای برنامه نویسی وب در پایتون با شما همراهان گرامی پلاتین به اشتراک گذاشته ایم. ممنون میشیم با دادن نظراتتون مارو حمایت کنید

پایده سازی الگوریتم base64 با پایتون

B64_CHARSET = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"


def base64_encode(data: bytes) -> bytes:
    """Encodes data according to RFC4648.

    The data is first transformed to binary and appended with binary digits so that its
    length becomes a multiple of 6, then each 6 binary digits will match a character in
    the B64_CHARSET string. The number of appended binary digits would later determine
    how many "=" signs should be added, the padding.
    For every 2 binary digits added, a "=" sign is added in the output.
    We can add any binary digits to make it a multiple of 6, for instance, consider the
    following example:
    "AA" -> 0010100100101001 -> 001010 010010 1001
    As can be seen above, 2 more binary digits should be added, so there's 4
    possibilities here: 00, 01, 10 or 11.
    That being said, Base64 encoding can be used in Steganography to hide data in these
    appended digits.

    >>> from base64 import b64encode
    >>> a = b"This pull request is part of Hacktoberfest20!"
    >>> b = b"https://tools.ietf.org/html/rfc4648"
    >>> c = b"A"
    >>> base64_encode(a) == b64encode(a)
    True
    >>> base64_encode(b) == b64encode(b)
    True
    >>> base64_encode(c) == b64encode(c)
    True
    >>> base64_encode("abc")
    Traceback (most recent call last):
      ...
    TypeError: a bytes-like object is required, not 'str'
    """
    # Make sure the supplied data is a bytes-like object
    if not isinstance(data, bytes):
        raise TypeError(
            f"a bytes-like object is required, not '{data.__class__.__name__}'"
        )

    binary_stream = "".join(bin(byte)[2:].zfill(8) for byte in data)

    padding_needed = len(binary_stream) % 6 != 0

    if padding_needed:
        # The padding that will be added later
        padding = b"=" * ((6 - len(binary_stream) % 6) // 2)

        # Append binary_stream with arbitrary binary digits (0's by default) to make its
        # length a multiple of 6.
        binary_stream += "0" * (6 - len(binary_stream) % 6)
    else:
        padding = b""

    # Encode every 6 binary digits to their corresponding Base64 character
    return (
        "".join(
            B64_CHARSET[int(binary_stream[index : index + 6], 2)]
            for index in range(0, len(binary_stream), 6)
        ).encode()
        + padding
    )


def base64_decode(encoded_data: str) -> bytes:
    """Decodes data according to RFC4648.

    This does the reverse operation of base64_encode.
    We first transform the encoded data back to a binary stream, take off the
    previously appended binary digits according to the padding, at this point we
    would have a binary stream whose length is multiple of 8, the last step is
    to convert every 8 bits to a byte.

    >>> from base64 import b64decode
    >>> a = "VGhpcyBwdWxsIHJlcXVlc3QgaXMgcGFydCBvZiBIYWNrdG9iZXJmZXN0MjAh"
    >>> b = "aHR0cHM6Ly90b29scy5pZXRmLm9yZy9odG1sL3JmYzQ2NDg="
    >>> c = "QQ=="
    >>> base64_decode(a) == b64decode(a)
    True
    >>> base64_decode(b) == b64decode(b)
    True
    >>> base64_decode(c) == b64decode(c)
    True
    >>> base64_decode("abc")
    Traceback (most recent call last):
      ...
    AssertionError: Incorrect padding
    """
    # Make sure encoded_data is either a string or a bytes-like object
    if not isinstance(encoded_data, bytes) and not isinstance(encoded_data, str):
        raise TypeError(
            "argument should be a bytes-like object or ASCII string, not "
            f"'{encoded_data.__class__.__name__}'"
        )

    # In case encoded_data is a bytes-like object, make sure it contains only
    # ASCII characters so we convert it to a string object
    if isinstance(encoded_data, bytes):
        try:
            encoded_data = encoded_data.decode("utf-8")
        except UnicodeDecodeError:
            raise ValueError("base64 encoded data should only contain ASCII characters")

    padding = encoded_data.count("=")

    # Check if the encoded string contains non base64 characters
    if padding:
        assert all(
            char in B64_CHARSET for char in encoded_data[:-padding]
        ), "Invalid base64 character(s) found."
    else:
        assert all(
            char in B64_CHARSET for char in encoded_data
        ), "Invalid base64 character(s) found."

    # Check the padding
    assert len(encoded_data) % 4 == 0 and padding < 3, "Incorrect padding"

    if padding:
        # Remove padding if there is one
        encoded_data = encoded_data[:-padding]

        binary_stream = "".join(
            bin(B64_CHARSET.index(char))[2:].zfill(6) for char in encoded_data
        )[: -padding * 2]
    else:
        binary_stream = "".join(
            bin(B64_CHARSET.index(char))[2:].zfill(6) for char in encoded_data
        )

    data = [
        int(binary_stream[index : index + 8], 2)
        for index in range(0, len(binary_stream), 8)
    ]

    return bytes(data)


if __name__ == "__main__":
    import doctest

    doctest.testmod()

مثله n وزیر با پایتون:

r"""
Problem:

The n queens problem is: placing N queens on a N * N chess board such that no queen
can attack any other queens placed on that chess board.  This means that one queen
cannot have any other queen on its horizontal, vertical and diagonal lines.

Solution:

To solve this problem we will use simple math. First we know the queen can move in all
the possible ways, we can simplify it in this: vertical, horizontal, diagonal left and
 diagonal right.

We can visualize it like this:

left diagonal = \
right diagonal = /

On a chessboard vertical movement could be the rows and horizontal movement could be
the columns.

In programming we can use an array, and in this array each index could be the rows and
each value in the array could be the column. For example:

    . Q . .     We have this chessboard with one queen in each column and each queen
    . . . Q     can't attack to each other.
    Q . . .     The array for this example would look like this: [1, 3, 0, 2]
    . . Q .

So if we use an array and we verify that each value in the array is different to each
other we know that at least the queens can't attack each other in horizontal and
vertical.

At this point we have it halfway completed and we will treat the chessboard as a
Cartesian plane.  Hereinafter we are going to remember basic math, so in the school we
learned this formula:

    Slope of a line:

           y2 - y1
     m = ----------
          x2 - x1

This formula allow us to get the slope. For the angles 45º (right diagonal) and 135º
(left diagonal) this formula gives us m = 1, and m = -1 respectively.

See::
https://www.enotes.com/homework-help/write-equation-line-that-hits-origin-45-degree-1474860

Then we have this other formula:

Slope intercept:

y = mx + b

b is where the line crosses the Y axis (to get more information see:
https://www.mathsisfun.com/y_intercept.html), if we change the formula to solve for b
we would have:

y - mx = b

And since we already have the m values for the angles 45º and 135º, this formula would
look like this:

45º: y - (1)x = b
45º: y - x = b

135º: y - (-1)x = b
135º: y + x = b

y = row
x = column

Applying these two formulas we can check if a queen in some position is being attacked
for another one or vice versa.

"""
from __future__ import annotations


def depth_first_search(
    possible_board: list[int],
    diagonal_right_collisions: list[int],
    diagonal_left_collisions: list[int],
    boards: list[list[str]],
    n: int,
) -> None:
    """
    >>> boards = []
    >>> depth_first_search([], [], [], boards, 4)
    >>> for board in boards:
    ...     print(board)
    ['. Q . . ', '. . . Q ', 'Q . . . ', '. . Q . ']
    ['. . Q . ', 'Q . . . ', '. . . Q ', '. Q . . ']
    """

    # Get next row in the current board (possible_board) to fill it with a queen
    row = len(possible_board)

    # If row is equal to the size of the board it means there are a queen in each row in
    # the current board (possible_board)
    if row == n:
        # We convert the variable possible_board that looks like this: [1, 3, 0, 2] to
        # this: ['. Q . . ', '. . . Q ', 'Q . . . ', '. . Q . ']
        boards.append([". " * i + "Q " + ". " * (n - 1 - i) for i in possible_board])
        return

    # We iterate each column in the row to find all possible results in each row
    for col in range(n):

        # We apply that we learned previously. First we check that in the current board
        # (possible_board) there are not other same value because if there is it means
        # that there are a collision in vertical. Then we apply the two formulas we
        # learned before:
        #
        # 45º: y - x = b or 45: row - col = b
        # 135º: y + x = b or row + col = b.
        #
        # And we verify if the results of this two formulas not exist in their variables
        # respectively.  (diagonal_right_collisions, diagonal_left_collisions)
        #
        # If any or these are True it means there is a collision so we continue to the
        # next value in the for loop.
        if (
            col in possible_board
            or row - col in diagonal_right_collisions
            or row + col in diagonal_left_collisions
        ):
            continue

        # If it is False we call dfs function again and we update the inputs
        depth_first_search(
            possible_board + [col],
            diagonal_right_collisions + [row - col],
            diagonal_left_collisions + [row + col],
            boards,
            n,
        )


def n_queens_solution(n: int) -> None:
    boards: list[list[str]] = []
    depth_first_search([], [], [], boards, n)

    # Print all the boards
    for board in boards:
        for column in board:
            print(column)
        print("")

    print(len(boards), "solutions were found.")


if __name__ == "__main__":
    import doctest

    doctest.testmod()
    n_queens_solution(4)

دانلود ویدیو اینستاگرام با پایتون

from datetime import datetime

import requests


def download_video(url: str) -> bytes:
    base_url = "https://downloadgram.net/wp-json/wppress/video-downloader/video?url="
    video_url = requests.get(base_url + url).json()[0]["urls"][0]["src"]
    return requests.get(video_url).content


if __name__ == "__main__":
    url = input("Enter Video/IGTV url: ").strip()
    file_name = f"{datetime.now():%Y-%m-%d_%H:%M:%S}.mp4"
    with open(file_name, "wb") as fp:
        fp.write(download_video(url))
    print(f"Done. Video saved to disk as {file_name}.")

خزنده جستوجوی گول با پایتون

import sys
import webbrowser

import requests
from bs4 import BeautifulSoup
from fake_useragent import UserAgent

if __name__ == "__main__":
    print("Googling.....")
    url = "https://www.google.com/search?q=" + " ".join(sys.argv[1:])
    res = requests.get(url, headers={"UserAgent": UserAgent().random})
    # res.raise_for_status()
    with open("project1a.html", "wb") as out_file:  # only for knowing the class
        for data in res.iter_content(10000):
            out_file.write(data)
    soup = BeautifulSoup(res.text, "html.parser")
    links = list(soup.select(".eZt8xd"))[:5]

    print(len(links))
    for link in links:
        if link.text == "Maps":
            webbrowser.open(link.get("href"))
        else:
            webbrowser.open(f"http://google.com{link.get('href')}")

دریافت اخبار BBC

# Created by sarathkaul on 12/11/19

import requests

_NEWS_API = "https://newsapi.org/v1/articles?source=bbc-news&sortBy=top&apiKey="


def fetch_bbc_news(bbc_news_api_key: str) -> None:
    # fetching a list of articles in json format
    bbc_news_page = requests.get(_NEWS_API + bbc_news_api_key).json()
    # each article in the list is a dict
    for i, article in enumerate(bbc_news_page["articles"], 1):
        print(f"{i}.) {article['title']}")


if __name__ == "__main__":
    fetch_bbc_news(bbc_news_api_key="<Your BBC News API key goes here>")

اطلاعات ویروس Coivid-19

"""
This is to show simple COVID19 info fetching from worldometers site using lxml
* The main motivation to use lxml in place of bs4 is that it is faster and therefore
more convenient to use in Python web projects (e.g. Django or Flask-based)
"""

from collections import namedtuple

import requests
from lxml import html  # type: ignore

covid_data = namedtuple("covid_data", "cases deaths recovered")


def covid_stats(url: str = "https://www.worldometers.info/coronavirus/") -> covid_data:
    xpath_str = '//div[@class = "maincounter-number"]/span/text()'
    return covid_data(*html.fromstring(requests.get(url).content).xpath(xpath_str))


fmt = """Total COVID-19 cases in the world: {}
Total deaths due to COVID-19 in the world: {}
Total COVID-19 patients recovered in the world: {}"""
print(fmt.format(*covid_stats()))

تبدیلات مالی با python

"""
This is used to convert the currency using the Amdoren Currency API
https://www.amdoren.com
"""

import os

import requests

URL_BASE = "https://www.amdoren.com/api/currency.php"
TESTING = os.getenv("CI", False)
API_KEY = os.getenv("AMDOREN_API_KEY", "")
if not API_KEY and not TESTING:
    raise KeyError("Please put your API key in an environment variable.")


# Currency and their description
list_of_currencies = """
AED	United Arab Emirates Dirham
AFN	Afghan Afghani
ALL	Albanian Lek
AMD	Armenian Dram
ANG	Netherlands Antillean Guilder
AOA	Angolan Kwanza
ARS	Argentine Peso
AUD	Australian Dollar
AWG	Aruban Florin
AZN	Azerbaijani Manat
BAM	Bosnia & Herzegovina Convertible Mark
BBD	Barbadian Dollar
BDT	Bangladeshi Taka
BGN	Bulgarian Lev
BHD	Bahraini Dinar
BIF	Burundian Franc
BMD	Bermudian Dollar
BND	Brunei Dollar
BOB	Bolivian Boliviano
BRL	Brazilian Real
BSD	Bahamian Dollar
BTN	Bhutanese Ngultrum
BWP	Botswana Pula
BYN	Belarus Ruble
BZD	Belize Dollar
CAD	Canadian Dollar
CDF	Congolese Franc
CHF	Swiss Franc
CLP	Chilean Peso
CNY	Chinese Yuan
COP	Colombian Peso
CRC	Costa Rican Colon
CUC	Cuban Convertible Peso
CVE	Cape Verdean Escudo
CZK	Czech Republic Koruna
DJF	Djiboutian Franc
DKK	Danish Krone
DOP	Dominican Peso
DZD	Algerian Dinar
EGP	Egyptian Pound
ERN	Eritrean Nakfa
ETB	Ethiopian Birr
EUR	Euro
FJD	Fiji Dollar
GBP	British Pound Sterling
GEL	Georgian Lari
GHS	Ghanaian Cedi
GIP	Gibraltar Pound
GMD	Gambian Dalasi
GNF	Guinea Franc
GTQ	Guatemalan Quetzal
GYD	Guyanaese Dollar
HKD	Hong Kong Dollar
HNL	Honduran Lempira
HRK	Croatian Kuna
HTG	Haiti Gourde
HUF	Hungarian Forint
IDR	Indonesian Rupiah
ILS	Israeli Shekel
INR	Indian Rupee
IQD	Iraqi Dinar
IRR	Iranian Rial
ISK	Icelandic Krona
JMD	Jamaican Dollar
JOD	Jordanian Dinar
JPY	Japanese Yen
KES	Kenyan Shilling
KGS	Kyrgystani Som
KHR	Cambodian Riel
KMF	Comorian Franc
KPW	North Korean Won
KRW	South Korean Won
KWD	Kuwaiti Dinar
KYD	Cayman Islands Dollar
KZT	Kazakhstan Tenge
LAK	Laotian Kip
LBP	Lebanese Pound
LKR	Sri Lankan Rupee
LRD	Liberian Dollar
LSL	Lesotho Loti
LYD	Libyan Dinar
MAD	Moroccan Dirham
MDL	Moldovan Leu
MGA	Malagasy Ariary
MKD	Macedonian Denar
MMK	Myanma Kyat
MNT	Mongolian Tugrik
MOP	Macau Pataca
MRO	Mauritanian Ouguiya
MUR	Mauritian Rupee
MVR	Maldivian Rufiyaa
MWK	Malawi Kwacha
MXN	Mexican Peso
MYR	Malaysian Ringgit
MZN	Mozambican Metical
NAD	Namibian Dollar
NGN	Nigerian Naira
NIO	Nicaragua Cordoba
NOK	Norwegian Krone
NPR	Nepalese Rupee
NZD	New Zealand Dollar
OMR	Omani Rial
PAB	Panamanian Balboa
PEN	Peruvian Nuevo Sol
PGK	Papua New Guinean Kina
PHP	Philippine Peso
PKR	Pakistani Rupee
PLN	Polish Zloty
PYG	Paraguayan Guarani
QAR	Qatari Riyal
RON	Romanian Leu
RSD	Serbian Dinar
RUB	Russian Ruble
RWF	Rwanda Franc
SAR	Saudi Riyal
SBD	Solomon Islands Dollar
SCR	Seychellois Rupee
SDG	Sudanese Pound
SEK	Swedish Krona
SGD	Singapore Dollar
SHP	Saint Helena Pound
SLL	Sierra Leonean Leone
SOS	Somali Shilling
SRD	Surinamese Dollar
SSP	South Sudanese Pound
STD	Sao Tome and Principe Dobra
SYP	Syrian Pound
SZL	Swazi Lilangeni
THB	Thai Baht
TJS	Tajikistan Somoni
TMT	Turkmenistani Manat
TND	Tunisian Dinar
TOP	Tonga Paanga
TRY	Turkish Lira
TTD	Trinidad and Tobago Dollar
TWD	New Taiwan Dollar
TZS	Tanzanian Shilling
UAH	Ukrainian Hryvnia
UGX	Ugandan Shilling
USD	United States Dollar
UYU	Uruguayan Peso
UZS	Uzbekistan Som
VEF	Venezuelan Bolivar
VND	Vietnamese Dong
VUV	Vanuatu Vatu
WST	Samoan Tala
XAF	Central African CFA franc
XCD	East Caribbean Dollar
XOF	West African CFA franc
XPF	CFP Franc
YER	Yemeni Rial
ZAR	South African Rand
ZMW	Zambian Kwacha
"""


def convert_currency(
    from_: str = "USD", to: str = "INR", amount: float = 1.0, api_key: str = API_KEY
) -> str:
    """https://www.amdoren.com/currency-api/"""
    params = locals()
    params["from"] = params.pop("from_")
    res = requests.get(URL_BASE, params=params).json()
    return str(res["amount"]) if res["error"] == 0 else res["error_message"]


if __name__ == "__main__":
    print(
        convert_currency(
            input("Enter from currency: ").strip(),
            input("Enter to currency: ").strip(),
            float(input("Enter the amount: ").strip()),
        )
    )

کد دریافت 250 فیلم برتر وب سایت IMDB

from __future__ import annotations

import csv

import requests
from bs4 import BeautifulSoup


def get_imdb_top_250_movies(url: str = "") -> dict[str, float]:
    url = url or "https://www.imdb.com/chart/top/?ref_=nv_mv_250"
    soup = BeautifulSoup(requests.get(url).text, "html.parser")
    titles = soup.find_all("td", attrs="titleColumn")
    ratings = soup.find_all("td", class_="ratingColumn imdbRating")
    return {
        title.a.text: float(rating.strong.text)
        for title, rating in zip(titles, ratings)
    }


def write_movies(filename: str = "IMDb_Top_250_Movies.csv") -> None:
    movies = get_imdb_top_250_movies()
    with open(filename, "w", newline="") as out_file:
        writer = csv.writer(out_file)
        writer.writerow(["Movie title", "IMDb rating"])
        for title, rating in movies.items():
            writer.writerow([title, rating])


if __name__ == "__main__":
    write_movies()